A good sized 24V inverter could use about as much power just being on as your lights do. If the lights consume 45 watts and run for 12 hours a day, the total power usage would be 45 watts x 12 hours = 540 watts. The battery power required for losses plus the load could double that. The lights themselves may be DC, using a small transformer (wall wart) to go from 120Vac to (likely) 12Vdc.
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20R at 48V is about 2.5A or therabouts, I''d suggest that will be just fine, give it a suitably rated switch and you''re good to go. You''re just trying to avoid that massive (almost infinite) current splat when you first connect the discharged inverter. The Seplos 48V BMS has a 51R 10W pre-charge resistor for about 1A pre-charge.
To size the kW rating of the resistors - follow these three simple rules. 1) For Brake times of 25 seconds and over, continuously rate the resistors at the power returning from the load - see note (a). 2) For braking times below 25 seconds, take the average power to be dissipated in the busiest 25 seconds.
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Could you please clarify this circuit with me? I have selected 90 ohms. Please let me know if I need to do something differently here. R=(24-30.3)/20mA= 1035ohm and I select 1Kohm I appreciate any ...
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Free QuoteIt has been suggested that the my inverter capacitors are sending too much inrush of current to the BMS & that a pre-charge resistor should solve this problem. What size pre …
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Free QuoteCould you please clarify this circuit with me? I have selected 90 ohms. Please let me know if I need to do something differently here. R=(24-30.3)/20mA= 1035ohm and I select …
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Free QuoteI saw Will use a resistor to eliminate the spark when first feeding power into an inverter. I’m going to buy a 24v inverter - around 2000 watts or maybe 1500, depending on the …
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